01 / Counting
Which digits count
Digits 1 to 9 always count. Zeros between them count. Leading zeros never count. Zeros after a decimal point at the end count.
Free tool
Type a number to see how many significant figures it has, with each digit marked as counted or not and the rule behind it. Round it to any number of sig figs, or switch to Calculate to add, subtract, multiply or divide two measurements and get the answer kept to the right precision, with the steps written out.
Try an example
Try an example
Write a number as 1500., 1.50e3 or 1.50 × 10^3 to show which zeros count. A trailing point means every digit counts.
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The rules
01 / Counting
Digits 1 to 9 always count. Zeros between them count. Leading zeros never count. Zeros after a decimal point at the end count.
02 / Adding
For + and −, the answer is kept to the coarsest place of any number in the sum.
03 / Multiplying
For × and ÷, the answer keeps as many significant figures as the number that has the fewest.
Guide
A significant figures calculator counts the digits in a number that carry information about how precisely it was measured. 0.00450 has 3 significant figures, 1500 has 2, and 1500. (with a point) has 4. This calculator marks each digit as counted or not, shows the rule that applied, rounds to any number of sig figs, and does addition, subtraction, multiplication and division while keeping the answer to the right precision.
The power of ten in scientific notation is never counted. 1.20 × 10^5 has 3, the same as 1.20.
Keep the first n counted digits and look at the next one. Round up if it is 5 or more, and down if it is less. 0.0045678 to 3 significant figures is 0.00457. 123456 to 2 is 120000, but that reads as 2 only by convention, so the calculator shows 1.2 × 10^5. When you need more figures than a number has, zeros are added: 2.5 to 4 is 2.500.
Choose Half to even if your course rounds exact ties to the even digit. 2.665 to 3 gives 2.67 half up but 2.66 half to even, because 6 is even. Most school work uses half up.
The answer is kept to the coarsest place of any number in the sum. 12.11 + 18.0 is exactly 30.11. 12.11 reaches the hundredths and 18.0 only the tenths, so the answer is rounded to the tenths: 30.1. For 5.673 − 2.1 the exact answer is 3.573, which becomes 3.6. A whole number with unclear zeros limits the answer too: 100 + 0.123 gives 100, because 100 is only known to the hundreds place.
The answer has as many significant figures as the number with the fewest. 4.56 × 1.4 is exactly 6.384. 1.4 has 2, so the answer is 6.4. 25.0 ÷ 3.00 is 8.3333 and both numbers have 3, so it is 8.33. An answer such as 2.50 × 4.0, which is 10 with 2 figures, is written 1.0 × 10^1 so that the zero is seen to count.
A count (12 eggs) or a defined factor (2.54 cm per inch) is exact and has no uncertainty, so it must not limit the answer. Tick A is exact or B is exact. Then 12 × 3.46 gives 41.5, kept to the 3 figures of 3.46, not to the 2 of the 12.
A beaker holds 24.35 g when full and 12.1 g when empty. Subtracting gives 12.25, which is rounded to the tenths place because 12.1 stops there, so the mass of liquid is 12.3 g half up (12.2 g with half to even, because the tie goes to the even digit). The liquid fills 8.0 mL. Dividing 12.3 by 8.0 gives 1.5375. Both numbers have 2 significant figures, so the density is 1.5 g/mL. If the volume had been read as 8.00 mL, the answer would carry 3 figures and be 1.54 g/mL. One extra zero on a reading changes the answer.
In a longer calculation, mixed steps are common. Work out an addition or subtraction first and keep its place, then use the count of figures it leaves for the multiplication that follows. Round at the very end, and use the Use the answer as A button only when you want to treat a rounded answer as a new measurement.
For general sums use the scientific calculator, and for the spread of a set of measurements try the standard deviation calculator.
Questions
Three: 4, 5 and the final 0. The zeros before the 4 only hold the place and do not count.
After a decimal point, yes. In a whole number with no point, such as 1500, they are usually not counted. Write 1500. or 1.50 × 10^3 to make the meaning clear.
Keep the first 3 counted digits, then round the third up if the next digit is 5 or more. 0.0045678 becomes 0.00457.
Keep the answer to the same decimal place as the least precise number. It is about places, not about the count of figures.
The answer keeps as many significant figures as the number with the fewest.
No. Only the digits in front count. 6.02 × 10^23 has 3, the same as 6.02.
A value with no uncertainty, such as a count of items or a defined unit factor. It has no limit on figures, so tick the exact box and it will not affect the answer.
This calculator counts a plain 0 as 1, and a value like 0.00 as 2, the zeros after the point. Books vary on this, so treat it as a convention.
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